1 files changed, 0 insertions, 58 deletions
diff --git a/src/main/model/util/Lexer.java b/src/main/model/util/Lexer.java
deleted file mode 100644
index b35caa6..0000000
--- a/src/main/model/util/Lexer.java
+++ /dev/null
@@ -1,58 +0,0 @@
-package model.util;
-
-import java.util.*;
-
-// General-purpose Lexer
-public class Lexer {
-
-    // private static final Set<String> whitespace = new HashSet<String>(" ", "\n");
-
-    // unused, helper function for if we implement finding identifers longer than a character
-    private static int longestDelimiter(Set<String> delimiters) {
-        int longestDelimiter = 0;
-        for (String delimiter : delimiters) {
-            if (delimiter.length() > longestDelimiter) {
-                longestDelimiter = delimiter.length();
-            }
-        }
-        return longestDelimiter;
-    }
-
-    /**
-     * Lexes a "free-form" language. "free-form" has a specific meaning here that's important to preserve:
-     * "free-form" means that _additional_ whitespace characters do not affect the language: e.g. two newlines
-     * instead of one, four spaces instead of two, etc. They are _not_ "whitespace-insensitive", which is usually
-     * a misnomer.
-     * The name's a bit of a joke: free-form languages are generally referred to as whitespace-insensitive -->
-     * insensitive == rude. Jokes are funnier when you have to explain them.
-     * Also, insensitiveLex() and freeformLex() aren't really that good of names.
-     *
-     * NOTE: This lexer only works with single-character deliminators.
-     * TODO: deduplicate whitespace
-     */
-    // public static ArrayList<String> rudeLex(String input, Set<Character> delimiters) {}
-
-    /**
-     * We might as well implement a lexer for non-free-form languages, but whatever. We won't use it.
-     */
-    public static ArrayList<String> sensitiveLex(String input, Set<Character> delimiters) {
-        // int longestDelimiter = longestDelimiter(delimiters);
-
-        ArrayList<String> tokens = new ArrayList<String>();
-        String currentToken = "";
-        // terrible c-style for loop because we may need to manipulate the index in the future
-        for (int i = 0; i < input.length(); i++) {
-            char nextToken = input.charAt(i);
-            if (delimiters.contains(nextToken)) {
-                if (!currentToken.equals("")) {
-                    tokens.add(currentToken);
-                }
-                tokens.add(Character.toString(nextToken));
-                currentToken = "";
-            } else {
-                currentToken += input.charAt(i);
-            }
-        }
-        return tokens;
-    }
-}